Factor by grouping

x(to the 3rd power) + 5x(to the 2nd power) + x +5

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Factor by grouping

x(to the 3rd power) + 5x(to the 2nd power) + x +5

x(to the 3rd power) + 5x(to the 2nd power) + x +5

- pleasehelp
**Posts:**1**Joined:**Sun May 04, 2014 12:59 am

Sorry for not replying sooner.

We usually don't help anyone that just types a problem without stating anything else. This is not a "we do your homework for you" site.

Do you know the basics of using 'grouping'?

Here is an example:

x^3 + 3x^2 - 6x - 18

This is similar to your problem but with some negatives in it. Your problem is easier.

Grouping means that you look for a couple terms with common factors. In

x^3 + 3x^2 - 6x - 18

You see that the first three terms have a common "x" but usually we do x^2 out of the first two.

Rewrite x^3 + 3x^2 as (x^2)(x+3) and notice that you can rewrite -6x-18 as

-6(x+3).

So now we have (x^2)(x+3) - 6(x+3)

Note that (x+3) is common. This is how these type of problems work out.

Factoring (x+3) from (x^2)(x+3) - 6(x+3) gives

(x+3)(x^2 - 6)

This can be hard to follow but let us know where you might be lost and we will help.

We usually don't help anyone that just types a problem without stating anything else. This is not a "we do your homework for you" site.

Do you know the basics of using 'grouping'?

Here is an example:

x^3 + 3x^2 - 6x - 18

This is similar to your problem but with some negatives in it. Your problem is easier.

Grouping means that you look for a couple terms with common factors. In

x^3 + 3x^2 - 6x - 18

You see that the first three terms have a common "x" but usually we do x^2 out of the first two.

Rewrite x^3 + 3x^2 as (x^2)(x+3) and notice that you can rewrite -6x-18 as

-6(x+3).

So now we have (x^2)(x+3) - 6(x+3)

Note that (x+3) is common. This is how these type of problems work out.

Factoring (x+3) from (x^2)(x+3) - 6(x+3) gives

(x+3)(x^2 - 6)

This can be hard to follow but let us know where you might be lost and we will help.

- the_hill1962
- PATH Tutor
**Posts:**102**Joined:**Tue Feb 19, 2008 1:23 pm**Location:**Texas, USA

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